If a 65kg woman is driving off a 10 meter platform, what is her speed as she hits the water?

Question

owlfred · Answer

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

anonymous · Answer

Use:$$v^2=u^2+2as$$

nowhereman · Answer

Why does this has to do anything with her weight?
Also this is a question for the physics section I would say.
(hint: earth speed up is $9.81 m/s^2$)

anonymous · Answer

$$v^2=u^2+2as$$
Where u=initial velocity=0m/s
a=g=9.81m/s^2
s=10m

anonymous · Answer

information not clear

anonymous · Answer

$$v^2=u^2+2as$$u=0, a=g=9.81ms^-2, s=h (height). So:$$v^2=0^2+2 \times g \times h=2 \times 9.81 \times10=196.2$$(Don't worry about units there). So:$$v=\sqrt{196.2}\approx14ms^{-1}$$