Question

Find the second derivative of the function

g(t) = -(4/((t+2)^2))

Answer 1

-4(t+2)^-2

Answer 2

g' = 8(t+2)

g'' = 8

Answer 3

ugh...soo close

Answer 4

thats a fraction

Answer 5

g' = 8(t+2)^-3

g'' = -24(t+2)^-4

Answer 6

hi amistre! -4/ (t+2)^2

Answer 7

\[g''=\frac{-24}{(t+2)^4}\]

Answer 8

oh nvm i see what u did sorry

Answer 9

product rule tends to be easier to follow that quotient rule

Answer 10

oh i used the quotient rule

Answer 11

for g't i got 8t+16/(t^2+4t+4)^2

Answer 12

we could test it by taking the -4 aside:

\[{1\over(t+2)^2}\iff \frac{(t+2)^2 0 - 2(t+2)}{(t+2)^4} \iff \frac{-2}{(t+2)^3}\]

Answer 13

but it just follows the product rule of it lol

Answer 14

for g''(t) i got -16t^4-192t^3-480t^2-384t-1008/ (t^4+8t^3+12t^2+32t+16)

Answer 15

\[g' = {8 \over (t+2)^3} \iff 8(t+2)^{-3} \]
right?

Answer 16

hmm confused

Answer 17

so what your saying is that our answers are the same? is my answer correct?

Answer 18

i dont see your answer as being correct; it looks like you got lost in the details

Answer 19

\[\frac{8}{(t+2)^3}\] doesnt turn into that

Answer 20

i'll just use the product rule

Answer 21

\[g'' = {-8.3(t+2)^2 \over (t+2)^6} \iff {-24 \over (t+2)^4}\]

Answer 22

because it can get pretty contangeled like this

Answer 23

product rule is simplest :)

Answer 24

thank you so much :)

Answer 25

yw :)