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Given: y= 2x^ -4x +3 find the vertex
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2x^2? x^2?
2x squared
k of vertex=-b/2a
Sorry, that was h, of vertex (h,k)
y =a(x-h)^2 +k
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i dont understand whats going on
The vertex you are looking for is given the name (h, k) y=2x^2 -4x + 3 y=ax^2 +bx +c Equation of the parabola may also be written in the form y=z(x-h)^2 +k
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