Question

can you halp me find the center of this circle please with this equation : x squared plus y squared plus 16x minus 16y plus 79=0

Answer 1

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Answer 2

x^2+y^2-16x-16y+79

Answer 3

complete the square

Answer 4

(x^2-16x+64)+(y^2-16y+64)=-79+128
(x-8)^2+(y-8)^2=...

Answer 5

adding on to what imranmeah91 already has, the center of the circle is located at the coordinates (-8,8). Although the computation that imranmeah91 has may be a little off.

Answer 6

- correction
x^2+y^2+16x-16y+79

Answer 7

(x^2+16x+64)

Answer 8

The actual equation for this particular circle is (x+8)^2+(x-8)^2=49

Answer 9

again, the circle has a center at (-8,8) with a radius of 7.

Answer 10

thank you