Question

I really need help...INVOLVES Calculus!

Answer 1

I got you :)

Answer 2

how messy of calculus?

Answer 3

Simplify \[2\log _{10}\sqrt{x} + 3\log _{10}x ^{1/3}\]

Answer 4

This isn't involving calculus as it stand but I can help you (or amistre64) if you wish.

Answer 5

we can both help ;)

Answer 6

rriic25, how much do you know about simplifying logarithms?

Answer 7

not much :(

Answer 8

2log(sqrt(x))+3log(x^1/3) ; get the 'exponents' to the front

2(1/2) log(x) + 3(1/3) log(x) ; do the math to clean it up

log(x) + log(x) ; when logs add, the innards multiply

log(x*x)

log(x^2) ; this is good, but if need be put the exponent in front

2 log(x)

Answer 9

I completely understand thank you very much

Answer 10

youre welcome :)