On the Fourth of July, 850 soft drinks were sold at a concession stand, some at $.72 each, the others at $.90 each. The receipts were $690. How many were sold at each price.

Use a system!

Question

On the Fourth of July, 850 soft drinks were sold at a concession stand, some at $.72 each, the others at $.90 each. The receipts were $690. How many were sold at each price.

Use a system!

anonymous · Answer

x+y=850
.72()+.90()=690

anonymous · Answer

Thks

anonymous · Answer

Can someone solve it?

amistre64 · Answer

c + p = 850

c = 850 - p
........................

c(.72) + p(.90) = 690

(850 - p)(.72) + p(.90) = 690

850(.72) -.72p +.90p = 690

 p(.90 -.72) = 690 - 850(.72)

 p = 690 - 850(.72)
         -----------
            .90 -.72 

 p = 433.333333

anonymous · Answer

$$.72x+.9(850-x)=690$$ should work

amistre64 · Answer

kinda odd to sell 1/3 of a pepsi lol

anonymous · Answer

really?

anonymous · Answer

that is about as much as i could drink. i am getting cranky time for lunch

amistre64 · Answer

as i see it, someone was skiming off the profits

anonymous · Answer

two  thirds pepsi, one third rum maybe?

amistre64 · Answer

:)  i may be a bad mormon in somethings; but that aint one of them lol

anonymous · Answer

;)

amistre64 · Answer

it might bode better to switch the coke and pepsi prices and see if a discrete amount comes up