how do you find the area the shaded region in a circle?
depends on the shaded regions; does it look like a peice of pie? or a trianlge? or a piece of pie that has the tip cut off? or
It looks like a pie with a piece missing .
The angle of the missing piece is 30 degrees
area will be 30/360 x pi r^2
This will be the area of the missing pie So area of left pie will be 320/360 x pi r^2 where r is radius of circle
convert 30 to radians; pi/6 now just use the area of a sector; \({\pi\over6}*{1\over2}* r^2\)
so the area of the shaded region is 25.12?
the area of the shaded region is: 2pi - what I gave you
@amistre Why do we need to convert to radians angle/360 x pi r^2 will give the area
we got no idea what your radius is
the radius is 3
\[angle * \frac{\pi}{180}\] is the conversion; not 360 right?
pi r^2 = area circle; (360/360) pi r^2 .... i spose it works :)
25.12 is correct
In India we use the formula tht i used
no conversion is required
well, you still convert; its just in the formula ;)
how would I do the problem in terms of pi? (pi = 3.14)
if you wanna keep the 'pi' just dont multiply by it
(320/360) r^2 by this method
whatever that number is; then tack on the pi
Then ans is 8 pi
Then how do I find the circumference of the circle in terms of pi?
but you said missing was 30; which would make it; 330/360 right?
this missing part has an angle of 30 degreess
then i see it as: \[\frac{33}{4}\pi\]
or 8.25 pi
here is the problem attatched
i am not able to open this type of file
The circle below has center O , and its radius is 3m . Given that the measure of angle AOB=30 , find the area of the shaded region and the length of ADB . Give exact answers in terms of pi , and be sure to include the correct units in your answer.
You know that the area of the whole circle is πr². You know that the number of degrees around the whole circle is 360°. Since you are given the angle of the shaded region, put that amount over 360° and you will have the fraction of the whole. Formula: Let A = angle of shaded region and r=radius: Area of shaded region = (A/360)(π r²) Example: if the angle of the shaded region is (making it easy) 90°, and the radius is 10, the area is: (90/360) π (10)² = ¼ (100) π = 25π approximately 78.54 sq. units hope i helped ;)
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