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Mathematics 20 Online
OpenStudy (anonymous):

differentiate the following function y= (e^x+7)+5 Please show me step by step

OpenStudy (anonymous):

\[y=e ^{x+7}+5\]

myininaya (myininaya):

y'=(x+7)'e^{x+7}

myininaya (myininaya):

y'=(1+0)e^{x+7}

myininaya (myininaya):

y'=e^{x+7}

OpenStudy (anonymous):

is it \[y=e^{x+7}+5\]?

OpenStudy (anonymous):

Yes Satellite73

OpenStudy (anonymous):

if so the derivative is just \[e^{x+7}\]

OpenStudy (anonymous):

what about the constant 5

myininaya (myininaya):

the derivative of a constant is 0

OpenStudy (anonymous):

constant is a line with slope zero so the derivative is 0

OpenStudy (anonymous):

well yes i thought that would be it becuase there is no x's next to it

OpenStudy (anonymous):

btw one way to think about \[e^{x+7}\] is \[e^xe^7\]

myininaya (myininaya):

i was fixing to say that

OpenStudy (anonymous):

ok thanks Myiniaya

myininaya (myininaya):

u r such a thunder stealer satellite

OpenStudy (anonymous):

and of course \[e^7\] is a constant and the derivative of \[e^x\] is \[e^x\] so that is the answer easi-ly

OpenStudy (anonymous):

so the answer would be \[e ^{x+7}\]

OpenStudy (anonymous):

thunder!

OpenStudy (anonymous):

yes

myininaya (myininaya):

lol

OpenStudy (anonymous):

Ok thanks soo much guys

OpenStudy (anonymous):

ok who wrote \[(x+7)' e^{x+7}\] not you was it?

myininaya (myininaya):

it was me why?

OpenStudy (anonymous):

no not i

OpenStudy (anonymous):

it is right i was just messing with you. right, but unnecessary. very slow tonight. frozen even. server i mean

myininaya (myininaya):

lol satellite likes to win against me, rmalik he is always in competition with me

OpenStudy (anonymous):

i am just jealous that is all. she got amistre's bike and i didn't

myininaya (myininaya):

it was virtual bike and i stole it

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