Mathematics
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OpenStudy (anonymous):
differentiate the following function
y= (e^x+7)+5
Please show me step by step
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OpenStudy (anonymous):
\[y=e ^{x+7}+5\]
myininaya (myininaya):
y'=(x+7)'e^{x+7}
myininaya (myininaya):
y'=(1+0)e^{x+7}
myininaya (myininaya):
y'=e^{x+7}
OpenStudy (anonymous):
is it
\[y=e^{x+7}+5\]?
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OpenStudy (anonymous):
Yes Satellite73
OpenStudy (anonymous):
if so the derivative is just
\[e^{x+7}\]
OpenStudy (anonymous):
what about the constant 5
myininaya (myininaya):
the derivative of a constant is 0
OpenStudy (anonymous):
constant is a line with slope zero so the derivative is 0
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OpenStudy (anonymous):
well yes i thought that would be it becuase there is no x's next to it
OpenStudy (anonymous):
btw one way to think about
\[e^{x+7}\] is
\[e^xe^7\]
myininaya (myininaya):
i was fixing to say that
OpenStudy (anonymous):
ok thanks Myiniaya
myininaya (myininaya):
u r such a thunder stealer satellite
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OpenStudy (anonymous):
and of course \[e^7\] is a constant and the derivative of
\[e^x\] is \[e^x\] so that is the answer easi-ly
OpenStudy (anonymous):
so the answer would be \[e ^{x+7}\]
OpenStudy (anonymous):
thunder!
OpenStudy (anonymous):
yes
myininaya (myininaya):
lol
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OpenStudy (anonymous):
Ok thanks soo much guys
OpenStudy (anonymous):
ok who wrote
\[(x+7)' e^{x+7}\] not you was it?
myininaya (myininaya):
it was me why?
OpenStudy (anonymous):
no not i
OpenStudy (anonymous):
it is right i was just messing with you. right, but unnecessary. very slow tonight. frozen even. server i mean
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myininaya (myininaya):
lol satellite likes to win against me, rmalik
he is always in competition with me
OpenStudy (anonymous):
i am just jealous that is all. she got amistre's bike and i didn't
myininaya (myininaya):
it was virtual bike and i stole it