Question

If tanA=2/3 and sinB =5/√41 and angles A and B are in Quadrant I, find the value of tan (A+B) showing all steps

Answer 1

use angle sum formula for tan
\[\tan(A+B) =\frac{tanA + tanB}{1-tanAtanB}\]
from sinB = 5/sqrt41 use trig identity sin^2+cos^2 =1
cosB = sqrt(1 - sinB^2)
cosB = 4/sqrt41
tanB = sinB/cosB = 5/4
tanA = 2/3
substitute these values into above formula
tan(A+B) = 23/2

Answer 2

http://openstudy.com/groups/mathematics/updates/4de8378a4c0e8b0bd6e7bbd8