Question

Indicate the equation of the line meeting the given conditions. Please put the equation in standard form.

Containing A(1, 3) and B(0, 2)

Answer 1

\[\frac{y-3}{3-2}=\frac{x-1}{1-0}\]

Answer 2

HUH?

Answer 3

i think onA(1, 3)=(x,y) ...y-3=m(x-1)...here m1=(y-3)/(x-1)
and B(0, 2)=(x,y),..........y-2=m(x-0)....m2=(y-2)/(x-0)

now if we assume their slope are equal m1=m2 that is
(y-3)/(x-1)= (y-2)/(x-0)
we can use the poinB(0,2) by plug in to the equation
(y-3) (x-1)
--------= -------- use A(1,3)
(y-2) (x-0)

y-3 x-1
--- = ----- therefore y-3=x-1 or y=x-2
3-2 1-0

Answer 4

i mean use the pointA(1,3) instead of B(0,2)....lol

Answer 5

wow is it clearer now..lol

Answer 6

hmm
equation of a line is y=mx+b, so start there
m=slope
b = y-intercept
we have 2 points so you can find slope of those points using slope formula
\[m = \frac{y _{2}-y _{1}}{x _{2}-x _{1}} = \frac{3-2}{1-0} = 1\]
Now find b by using one of the points
3 = (1)(1) +b
3-1 = b
2 = b
Now the equation of the line through the 2 points is:
y = x +2
standard form is
ax + by = c
move the x to other side
-x + y = 2
done :)