Question

√5 - 3
-------
√5 - 2

Answer 1

how could you show 1/2 as a different fraction? same concept here

Answer 2

multiply both numerator and denominator by \[\sqrt{5} + 2\]

Answer 3

am i wrong?

Answer 4

then rationalise and u'll get the ans

say if u need working

Answer 5

basketmath, u r on the wrong track

in this question we have to rationalise the denominator

Answer 6

right... so you would multiply both. that's where i was going with it

Answer 7

if it were \[\sqrt[3]{5} - 2\] you would need to multiply by sqrt(5)^2+2 right?

Answer 8

in yr number above is it sqrt5 or cubert5????

Answer 9

cubert of 5

Answer 10

@marguerite

final answer is -(root5 +1) or -root5 -1

Answer 11

to get 5 out of the cubert you would need to multiply by sqrt(5)^2

Answer 12

so how would i write that?

Answer 13

the final answer or ???

Answer 14

the final answer

Answer 15

\[-(\sqrt{5} +1)\]

Answer 16

thank you!

Answer 17

can you show your work
i got: \[\sqrt{5}^2 - 3 \over 2\]

Answer 18

-2*

Answer 19

@basketmath for yr previous query

we will have to multiply it by cuberoot(5^2) + 2

Answer 20

ok ill show the working

Answer 21

root5 - 3 root5 + 2
--------- x ---------
root5 - 2 root5 + 2

(root5)^2 + 2root5 - 3root5 -6
----------------------------
(root5)^2 - 2^2

5 - root5 - 6
-----------
5 - 4

-root5 - 1
---------
1


-(root5 +1)

Answer 22

Hope it is clear now.....:)

Answer 23

Hey marguerite, if it is clear for u, pls click the good answer button for me

Answer 24

Hey basketmaths, where r u???? hv u seen the working????