Find the exact value of the following expression. If undefined, state, undefined. sec((cot^(-1)(5/12))
can some one pls write this down step by step: I ma going nuts trying to use the the identity
sec2x=1+tan2x
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OpenStudy (anonymous):
do I first change cot to tan? then square it?
OpenStudy (anonymous):
Akileez i explained this earlier on - check it out.
OpenStudy (anonymous):
thanks uzma; I knwo you replied previously to it
OpenStudy (anonymous):
I know jimmyrep; I wen tover it again and was confused
OpenStudy (anonymous):
cot^-1(5/12)=x
5/12=cotx
tanx=12/5
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OpenStudy (anonymous):
I did< i understand from using a right angles triangle. but i want to understand from a substitution perspective too.
OpenStudy (anonymous):
now use the identity
OpenStudy (anonymous):
oh ok yes change cot to tan tan = 1/cot then square it and plug it into the formula
OpenStudy (anonymous):
ok got that, but what about the sec in front after using the identity?
OpenStudy (anonymous):
take the sqrt
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OpenStudy (anonymous):
and how/why can you put an equals sign from tan(12/5) to tanx=12/5
OpenStudy (anonymous):
is it by adding the x component?
OpenStudy (anonymous):
\[secx=\sqrt{1+(12/5)^2}\]
OpenStudy (anonymous):
cotx=5/12
i/tanx=5/12
tanx=12/5
OpenStudy (anonymous):
cot is the reciprocal of tan
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OpenStudy (anonymous):
yes, got that
OpenStudy (anonymous):
this is what i get:
OpenStudy (anonymous):
sec(sec^2x=25/144)
OpenStudy (anonymous):
sec(sec^2x=(25/144) + 1)
OpenStudy (anonymous):
how come?
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OpenStudy (anonymous):
just solve what i posted earlier
OpenStudy (anonymous):
I'll show you what I did: sec(tan(5/12))
OpenStudy (anonymous):
now I originally changed tan to sin over cos and changed sec to I/cos - but that left me with sin
OpenStudy (anonymous):
my issue is that I do not see how you manage to cancel the trig funtions out and come up with just a number
OpenStudy (anonymous):
I really appreciate your help as this is bothering me as it shld be so obvious,
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OpenStudy (anonymous):
u r not need to change it, we have got the value of tanx, plug it into the identity n do the computations
OpenStudy (anonymous):
its ok, just be clear at ur end :)
OpenStudy (anonymous):
will do:
OpenStudy (anonymous):
can we start with the cot^-1 part first ?
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
u post what u think
OpenStudy (anonymous):
that would change to tan
OpenStudy (anonymous):
therefore you now have sec(tan(5/12)) - is that true>?
OpenStudy (anonymous):
no its not right
OpenStudy (anonymous):
ok, this is where I am stumped - sorry.
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OpenStudy (anonymous):
let
cot^-1(5/12)=x
5/12=cotx
tanx=12/5
OpenStudy (anonymous):
ok?
OpenStudy (anonymous):
remind that what is x taken to be
OpenStudy (anonymous):
ok, got that - forgot the ^(-1)
OpenStudy (anonymous):
therefore it shld now read sec(tan(12/5))
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OpenStudy (anonymous):
is that correct?
OpenStudy (anonymous):
now dealing with the tan part first: now, tan^2x+(12/5)^2 is that right?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
ok, so what goes after sec(tan(12/5)) ?
OpenStudy (anonymous):
or are you first dealing with tanx=12/5?
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OpenStudy (anonymous):
how did u get it?
OpenStudy (anonymous):
yes after getting tanx=12/5
use the identity
OpenStudy (anonymous):
sec x
OpenStudy (anonymous):
ok great: then after squaring: I will have sec^2x-1=144/25
OpenStudy (anonymous):
= (144/25) - 1
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OpenStudy (anonymous):
sec^2x=1+144/25
OpenStudy (anonymous):
i have an idea. draw a 5 - 12 - 13 right triangle. cotangent is "adjacent over opposite" so label the angle accordingly. that is label the angle whose opposite adjacent side is 5 and whose opposite side is 12. then all the other trig functions of that angle should be obvious
OpenStudy (anonymous):
( sorry plus one) then I will have to solve: sec(1 +144/25)
OpenStudy (anonymous):
yes sat.. u r right, but he/she wanted to do with identity :)
OpenStudy (anonymous):
sec x=13/5
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OpenStudy (anonymous):
thanks anyway Sat
OpenStudy (anonymous):
so you dont solve it further?
OpenStudy (anonymous):
it is done , y further?
OpenStudy (anonymous):
what I mean is:
OpenStudy (anonymous):
ok do it the hard way, fine with me!
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OpenStudy (anonymous):
:)
OpenStudy (anonymous):
you have sec(169/25) right?
OpenStudy (anonymous):
haha; sorry, hard way it is
OpenStudy (anonymous):
no no,
OpenStudy (anonymous):
actually it became hardest :P
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OpenStudy (anonymous):
from sec(144/25+1)
OpenStudy (anonymous):
all the identities come right out of the triangle anyway. i will be quiet now
OpenStudy (anonymous):
haha; i am sooooo sorry: that i am such a pain, just really want to get it
OpenStudy (anonymous):
now satellite is here, he is so sweet, would make u understand
OpenStudy (anonymous):
its ok, no pain, no gain :)
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OpenStudy (anonymous):
up to this part: sec^2x=1+144/25
OpenStudy (anonymous):
right
OpenStudy (anonymous):
take squre root
OpenStudy (anonymous):
oh first simplify the right side
OpenStudy (anonymous):
ok, that leaves us with sec 13/5
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OpenStudy (anonymous):
sorry; first simplify
OpenStudy (anonymous):
u missed x again
OpenStudy (anonymous):
169/25
OpenStudy (anonymous):
sec^2x =169/25
OpenStudy (anonymous):
so sec^2(x) = 169/25
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OpenStudy (anonymous):
sec x=13/5
OpenStudy (anonymous):
therefore sec =13/5
OpenStudy (anonymous):
my issue i show we did away with the sec outside the (cot^(-1)(5/12)) - am I being clear?
OpenStudy (anonymous):
yup :)
OpenStudy (anonymous):
when u get secx =13/5
put the value of x back
sec(cot^(-1)(5/12)=13/5
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OpenStudy (anonymous):
oh now I see!!!
OpenStudy (anonymous):
yay!!! i am so happy! thank you millions and millions!
OpenStudy (anonymous):
my pleasure, if i made u understand, i m done
OpenStudy (anonymous):
practically it all came dow to saying let cot^(-1)(5/12) = x
OpenStudy (anonymous):
you rock!!!
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OpenStudy (anonymous):
hahaha, i asked u keep it in mind
OpenStudy (anonymous):
I was so busy trying to cross out the trig functions, that's why I missed it all the time