A 0.944 M solution of glucose,C6H12O6 , in water has a density of 1.0624g/ml at 20degree Celcius. What is the concentration of this solution in the following units?
Mole fraction ? Mass Percent? Molality

Question

A 0.944 M solution of glucose,C6H12O6 , in water has a density of 1.0624g/ml  at 20degree Celcius. What is the concentration of this solution in the following units?
Mole fraction ? Mass Percent? Molality

owlfred · Answer

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anonymous · Answer

mass of C6H12O6=72+12+96=180.
M=moles/litre  ,so moles of glucose per litre=0.944.
mass per litre=0.944*180=169.92g
total mass per litre = 1062.4g
Hence mass of water=1062.4-169.92=894.28.
moles of C6H12O6=0.944
mass of solvent in kg=0.89428
Molality is moles/mass of solvent = 0.944/0.894=1.055m

anonymous · Answer

Moles of water=894.28/18=49.68
Moles of glucose=0.944
Mole fraction=0.944/(0.944+49.68)=0.018.
mass percent=169.92*100/(169.92+894.28)= 169.92*100/1062.4=0.15*100=15%.