Question

Help with triple integration plsss

Answer 1

post it..

Answer 2

Please help me...

Answer 3

first intrgrate it with respect to z that will give u z^3/3 put the limit and u will get a function of x and y, then integrate it with respect to y and u will get a function of x only and then do it with x

Answer 4

yeah i tried..its really hard, that 's y they are asking us to do it using spherical or cylindrical cords

Answer 5

Use polar coordinates, it will be easy. \(x^2+y^2=r^2\), \(y=r \sin \theta\).

Answer 6

ya but I dnt understand what my boundaries should be in polar coordinates.

Answer 7

\(\sqrt{x^2+y^2}=\sqrt{r^2}=r\), \(\sqrt{72-(x^2+y^2)}=\sqrt{72-r^2}\) and \(\sqrt{36-y^2}=\sqrt{36-r^2\sin^2\theta}\).