PLZ HELP THANKS!
Find the partial fraction decomposition for the rational expression.
8x+236
OVER
(x+7)(x+2)(x+13)
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OpenStudy (anonymous):
you want the snap way?
OpenStudy (anonymous):
ha i dont know the best way i ges
OpenStudy (anonymous):
best way is snap way. write it down nice and large. you want to know what number goes over the factor (x+7)
OpenStudy (anonymous):
x + 7 = 0 means x = -7
OpenStudy (anonymous):
put replace x everywhere you see it by -7, but ignore the factor of x + 7 in the denominator
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OpenStudy (anonymous):
o ok
OpenStudy (anonymous):
get
\[\frac{8\times -7+236}{(-7+2)(-7+13)}\]
OpenStudy (anonymous):
this is what goes over the x + 7 term
OpenStudy (anonymous):
is that the final answer?
OpenStudy (anonymous):
oh no
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OpenStudy (anonymous):
that is just A here
\[\frac{A}{x+7}\]
OpenStudy (anonymous):
so we just found a now we plug that in for?
OpenStudy (anonymous):
yup that is A
OpenStudy (anonymous):
lets make sure it is clear what the goal is. you want to write
\[\frac{8x+263}{(x+7)(x+2)(x+13)}=\frac{A}{x+7}+\frac{B}{x+2}+\frac{C}{x+13}\]
OpenStudy (anonymous):
so your job is finding A, B, and C
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so we can find A as i said. put your hand over the x+7 part and just replace x everywhere by -7
OpenStudy (anonymous):
then how i find the others?
OpenStudy (anonymous):
did you get -6?
OpenStudy (anonymous):
or did i mess up?
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OpenStudy (anonymous):
o I was not woorking it I was just trying to get how to then was going to do the whole thing
OpenStudy (anonymous):
maybe it is -36 by calculator is off
OpenStudy (anonymous):
so how would i find the others after i find a?
haha
OpenStudy (anonymous):
ok lets assume we can do it. the computation is
\[\frac{-7\times 8+236}{(-7+2)(-7+13)}\]
OpenStudy (anonymous):
we do the others exactly the same way
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OpenStudy (anonymous):
we want to know what goes over x+2
OpenStudy (anonymous):
x+2 = 0 means x = -2. put your hand over that factor and then replace all x's by -2
OpenStudy (anonymous):
o ok!
OpenStudy (anonymous):
the computation is
\[\frac{8\times -2+236}{(-2+7)(-2+13)}\]
OpenStudy (anonymous):
and for the third guess what?
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OpenStudy (anonymous):
\[\frac{8\times -13+236}{(-13+7)(-13+2)}\]
OpenStudy (anonymous):
first one goes over x+7
second goes over x+2
third goes over x+13
OpenStudy (anonymous):
apparently i am too stupid to actually calculate these numbers but they are the ones you want
OpenStudy (anonymous):
i will try them, let me know what you get
OpenStudy (anonymous):
then we can write the "final answer"
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OpenStudy (anonymous):
ha ok ok, let me see if i got this you take one x value from bottom and find x then plug it in to ever x in the problem and do that with all of them then you have three problems and do you solve thos and how?
OpenStudy (anonymous):
then you are done. you need to find A, B and C
OpenStudy (anonymous):
then just write the answer.
OpenStudy (anonymous):
\[A=\frac{8\times (-7)+236}{(-7+2)(-7+13)}\]
OpenStudy (anonymous):
whatever that number is, that is A the number that goes over x + 7
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OpenStudy (anonymous):
if i had a better calculator i could compute it quickly.
OpenStudy (anonymous):
how do i do it without calculator or really bad calculator?
OpenStudy (anonymous):
well -8*7=-56
OpenStudy (anonymous):
236-56=180
OpenStudy (anonymous):
numerator is 180
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OpenStudy (anonymous):
(-7+2)(-7+13)=-5*-5=25
OpenStudy (anonymous):
and 180/25=36/5
OpenStudy (anonymous):
i guess. did i do it right?
OpenStudy (anonymous):
no i didn't
OpenStudy (anonymous):
(-7+2)(-7+13)=-5*6=-30
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OpenStudy (anonymous):
180/-30=-6
OpenStudy (anonymous):
so A = -6 and one term will be
\[\frac{-6}{x+7}\]
OpenStudy (anonymous):
\[B=\frac{8\times(-2)+236}{(-2+7)(-2+13)}\]
OpenStudy (anonymous):
what will the last term be over 13?
OpenStudy (anonymous):
the last one will be over x+13
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OpenStudy (anonymous):
yes and that is c?
OpenStudy (anonymous):
yes C
OpenStudy (anonymous):
we didn't compute it yet
OpenStudy (anonymous):
did you get B?
OpenStudy (anonymous):
could we
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OpenStudy (anonymous):
i wrote it above, do you see it? i just didn't compute it yet
OpenStudy (anonymous):
no this one looks harder then i will do b
OpenStudy (anonymous):
ok let me know what you get and i will check it
OpenStudy (anonymous):
i got a number for C
OpenStudy (anonymous):
ha not yet
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OpenStudy (anonymous):
4/x+2
OpenStudy (anonymous):
use a calculator it is easier that way
OpenStudy (anonymous):
oh that is B i didn't compute that one hold on
OpenStudy (anonymous):
i computed C
OpenStudy (anonymous):
ya wht u get
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OpenStudy (anonymous):
2
OpenStudy (anonymous):
positive>?
OpenStudy (anonymous):
i did get 4 for B yes
OpenStudy (anonymous):
yes i got positive 2
OpenStudy (anonymous):
ok thanks!
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