what is the integral of sin^2x dx?
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sin^2(x)=(1-cos(2x))/2
thanks
you're welcome :). And if you integrate sin^2(x) over one or more full "loops" there is a trick since the average of sin^2(x) over a period is 1/2
for example: \[\int\limits_{0}^{\pi}\sin^2(x)dx=\frac{\pi \int\limits_{0}^{\pi}\sin^2(x)dx}{\pi}=\frac{\pi}{2}\]
I am an engineer:) I have to solve this basic equation:)
allright then I geuss don't worry about it:)
I have calculus final today and I forgot the integral of sin^2x:D
oh allright well you can just use the trig identity. integral of cos^2 is similar: cos^2(x)=(1+cos(2x))/2
these are just the trig identities you still have to integrate by the way
int sin^2(x)= (x/2)-(sin(2x)/4)+C
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