Question

evaluate the limit as x goes to 0:
((x(3+x))/(6x^2)

Answer 1

1/6

Answer 2

the trick here is to see if we can cancel the part that is giving troubles

Answer 3

u can use l'hospital though :)

Answer 4

\[\frac{x(3+x)}{6.x.x}\]

Answer 5

aaaagh! that is what I missed! Thank you!

Answer 6

\[\frac{3+x}{6x}\]
\[\frac{3}{6x}+\frac{x}{6x}\]

Answer 7

that was a tricky one - thanks for explaining so well!!!

Answer 8

i/1 though is not one of my choices?

Answer 9

1/6

Answer 10

you will always have an undefined in the denom anyway

Answer 11

what are your choices?

Answer 12

1/2
DNE
-3
0
3

Answer 13

must be DNE

Answer 14

its DNE; the one sided limits dont agree

Answer 15

that's what I got yay!

Answer 16

http://www.wolframalpha.com/input/?i=lim {x+to+0}%28%28x%283%2Bx%29%29%2F%286x^2%29

for clarification :)

Answer 17

it cuts the link short .... bummer

Answer 18

thanks anyway

Answer 19

nope for this u should not split and evaluate the limit... u need to apply the l'hospital rule directly, this'll giv u the correct answer.