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OpenStudy (anonymous):

For the following limit, find the largest δ that works for ε = 0.01 (attached equation)

OpenStudy (anonymous):

OpenStudy (anonymous):

you want to solve this \[|\frac{1}{5}x-\frac{5}{7}|<.001 \] for x

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

\|[\frac{1}{5}x-\frac{7}{5}|<.001\]

OpenStudy (anonymous):

damn! \[|\frac{1}{5}x-\frac{7}{5}|<.001\]

OpenStudy (anonymous):

wat went wrong? u missed some symbol?

OpenStudy (anonymous):

the (1/5)x is confusing me

OpenStudy (anonymous):

that is what i want. ok finally. we solve easily \[-.001<\frac{1}{5}x-\frac{7}{5}<.001\] \[\frac{7}{5}-.001<\frac{1}{5}x<\frac{7}{5}+.001\] \[7-.005<x<7+.005\]

OpenStudy (anonymous):

the last line means \[|x-7|<.005\] and you are done

OpenStudy (anonymous):

I got 1/20

OpenStudy (anonymous):

@akileez : u need to find δ such that |x-7|<δ => 7-δ<x<7+δ now use the value from x as given by satellite to find the range of δ.

OpenStudy (anonymous):

\[\delta = .005\]and if you replace .001 by \[\epsilon\] you will get \[\delta= 5\epsilon\]

OpenStudy (anonymous):

nice latex brackett! keep it up

OpenStudy (anonymous):

that's what I did and I have absolute(x/5-7/5)< 0.01

OpenStudy (anonymous):

pulled out 1/5 as common factor which gave me: absolute(x-7)<5*0.01

OpenStudy (anonymous):

ok i was not paying sufficient attention. it should be .01 instead of .001 but you see that it makes no difference at all. you will get .05 instead of .005 no problem

OpenStudy (anonymous):

yeah you got it

OpenStudy (anonymous):

ok, I see, was jsut a typo - formula was spot on though! so the answer is 1/20?

OpenStudy (anonymous):

lines are easy to work with

OpenStudy (anonymous):

btw how do you mange to type using all the correct symbols - it"s awesome!

OpenStudy (anonymous):

right i used .001 you used .01 you should try it with \[\epsilon\] and get a general answer

OpenStudy (anonymous):

i can show you in chat, but i cannot show you here because they will come up as symbols

OpenStudy (anonymous):

if you want come to chat and i can show you the basics easily

OpenStudy (anonymous):

sweet, how do I go to chat?

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