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evaluate the integral from 0 to pie/4. sec^2theta dtheta
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\(\int_{}\)sec^2(t) dt
well, D(tan(t)) = sec^2(t) ; so start with that ;)
cool i did it that way
the i plug the values and subtract f(b)-f(a)
trig stuff is alot of memorization ....
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yes; f(higher bound) - f(lower bound)
tan(pi/4) - tan(0)
cool
:)
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