Question

add:
6 9
-- -- + -----
(X+4) (X-3)

Answer 1

(15x+44)/(x^2-x+12)

Answer 2

\[\frac{6}{x+4}+\frac{9}{x-3}=\frac{6(x-3)+9(x+4)}{(x+4)(x+3)}\]

Answer 3

multiply out in the numerator and combine like terms you will get what dheeraj wrote

Answer 4

or maybe not lets check
\[6(x-3)+9(x+4)=6x-18+9x+36\]
\[15x-18\]hmm i get
\[\frac{15x-18}{(x-3)(x+4)}\]