This is Geometry: Find the volume, to the nearest hundredth, of a cone with a slant height 13 feet and radius 5 feet.…
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well; \[V_{cone}=(1/3)(base.area)(height)\]
base area is a circle so pi 5^2 = 25pi height has to be calculated for a rt tri with leg5 and leg13
why are people stealing my question???
simply plug in the given values into the equation: \[V=1/3(\pi)(r^2)((h)\]
thankyou amistre
sqrt(196+25) = sqrt(221) if i did it right
youre welcome :)
well bbb i proved u right again u were too ugly so no one answered u
13^2 = 169 ...tho right lol
here is the muliple choice for that question
no lmao ur just jealous so go shave urself
169 +25 ---- 194 sqrt(194) = height then
openstudy rule of answering #112: If a question remains unanswered for .002 secs, it becomes free for any and all participants ;)
A. 136.14 ft cube B. 314.16 ft cube C. 340.34 ft cube D. 408.141 ft cube
\[V_{cone}=\frac{25pi.\sqrt{194}}{3}\] if I did it right ...
so im guessing nobody knows the answer to the question
there was a question?
the question that stupid lmao put was originally mine not his or hers. and i put the multiple choice to prove it was mine
ohhh.... someone pilfered your q ... got it.
so; base area = 25pi; height = sqrt(13^2+5^2) Vcone = [25pi * sqrt(194)]/3 = abt 364.64...
sooooo close its either C or D ... C is 340.34 ft cube and D. is 408.41 ft cube
check to make sure all the info is right; you got a slant of 13 and a rad of 5?
i see my mistake then
\[h^2 + 5^2 = 13^2\] \[h=\sqrt{(169-25)}\] \[\h = \sqrt{144}=12]
.... h = 12 25pi*12 ------ = 25pi *4 = 100pi, abt 314.16 3
yes and that is correct thank you sooo much
had to fight it tooth and nail, but I got it :)
i know you did a good good and you got urself another fan :D
:) thnx
ur welcome :D
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