Question

For the equation y=(x+27)^2/3 -1, find the coordinates of the point(s) at which the graph crosses or touches the coordinate axes, if they exist.

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

x=-26

Answer 3

(-26,0) and (0,8)

Answer 4

The answers it gives me are (-26,0),(-28,0),(0,8)

Answer 5

yes thats true...

Answer 6

however i have no clue how to get to those answers myself

Answer 7

put x=0

Answer 8

y=(27)^3/2-1
y=9-1=8

Answer 9

yea i got that one

Answer 10

its the x values that get me

Answer 11

and put y=0
then 0=(x+27)^2/3-1
1=(x+27)^2/3
1=(x+27)^2
(x+27)=+-1
x=-26 or -28

Answer 12

i think its clear now...

Answer 13

thanks alot ill try a few with your examples

Answer 14

still trying to figure out where the 2/3 plays in lol