Question

tan^-1(x)/(1+x^2) u substitution.

Answer 1

I get u = Tan^-1 du = dx/1+x^2 and the solutions manual throws the answer as (tan^-1)^2/2.

Answer 2

\[(\tan^{-1} (x))^2/ 2\]

Answer 3

is it [tan^-1 (x)] / 1 + x^2??

Answer 4

Yes that is the original.

Answer 5

u = tan^-1 (x)
du = dx/(1+x^2)
so u can write
tdt

Answer 6

I don't understand how replacing the bottom half of the equation with dx/1+x^2 yields 2.

Answer 7

if u replace dx/ 1+x^2 by du
and tan^-1 (X) by u
ull be left with u.du
which is u^2 / 2

Answer 8

Oh I see thanks again.