Question

Solve for d.
sqrt--d^2+1 =1-d

Answer 1

\[\sqrt{d^2-1}=1-d\]

Answer 2

\[is this: \sqrt{d ^{2}+1}=1-d ?\]

Answer 3

yes angela thats the exact problem (:

Answer 4

if it is :
\[d ^{2}+1=(1-d)^{2}\]
solve it for d

Answer 5

angela has the correct format of the problem

Answer 6

\[d ^{2}+1=1-2d+d ^{2}\]

Answer 7

d=1

Answer 8

d^2-1=(1-d)^2
d^2-1=1-2d-d^2
d^2-1-1+2d+d^2=0
2d^2+2d-2=0
d^2+d-1=0
D=b^2-4ac=1-4*1*(-1)=5
d1=(-1-sqr5)/2
d2=(sqr5-1)2

Answer 9

1d2=(-b+-sqrD)/2a

Answer 10

\[d ^{2} - canceled out as well as 1\]
d=0

Answer 11

inik is right

Answer 12

angela21073..
per original: should be d^2 +1 (not -)...?

Answer 13

it is 0

Answer 14

good :)

Answer 15

d=0

Answer 16

sorry didn't get it...where? can u write it?

Answer 17

I got it

Answer 18

:(:(:( All that for nothing :(:(:(:( Sorry Jazmine :(

Answer 19

its okay angela u have helped me alot before too (: its just one mistake