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lim as x goes to 0: (2sinxcosx)/2x
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Can you break that up into a product?
And simplify it a bit. There's an important limit you should know that makes this easier.
not certain
=1
Yes, but why.
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i just crossed out and used teh rules
sinx/x and cosx/x
not quite right.
whoops the cosx is wrong
\[{2(sinx)(cosx) \over 2x}\]\[={(sinx)\over x}(cosx)\]
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The limit as x goes to 0 of cos x is 1. The limit as x goes to 0 of sinx/x = 1. So the whole limit is 1*1 = 1.
i see cos of zero is 1
thank you!
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