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Mathematics 18 Online
OpenStudy (anonymous):

lim as x goes to 0: (2sinxcosx)/2x

OpenStudy (anonymous):

Can you break that up into a product?

OpenStudy (anonymous):

And simplify it a bit. There's an important limit you should know that makes this easier.

OpenStudy (anonymous):

not certain

OpenStudy (anonymous):

=1

OpenStudy (anonymous):

Yes, but why.

OpenStudy (anonymous):

i just crossed out and used teh rules

OpenStudy (anonymous):

sinx/x and cosx/x

OpenStudy (anonymous):

not quite right.

OpenStudy (anonymous):

whoops the cosx is wrong

OpenStudy (anonymous):

\[{2(sinx)(cosx) \over 2x}\]\[={(sinx)\over x}(cosx)\]

OpenStudy (anonymous):

The limit as x goes to 0 of cos x is 1. The limit as x goes to 0 of sinx/x = 1. So the whole limit is 1*1 = 1.

OpenStudy (anonymous):

i see cos of zero is 1

OpenStudy (anonymous):

thank you!

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