Question

solve for k.
(k+2)^2=3
express answer in simplest form

Answer 1

\[This\ is\ of\ the\ form\ (a + b)^2\] \[k^2 + 4 + 4k = 3, k^2 + 4k = -1\]
\[k^2 + 4k +1 = 0, k(k+4) +1 = 0\]
\[(k+1)= 0 \ or\ (k+4) = 0, so \ k = -1 \ or\ k = -4\]

Answer 2

It is in its simplest form already. If you're trying to find the roots, here we go:
\[k+2=\pm \sqrt{3}\]
\[k=\pm \sqrt{3}-2\]

There are two solutions.