3x=9 - 6y 3x+8y=9
Take \(-6y\) from the first equation to the other side. Your system of equations will then be: \(3x+6y=9\) (1) \(3x+8y=9\) (2) Subtract (2) from (1), you get: \(-2y=0\implies y=0\). Now substitute \(y=0\) in either equation, you get \(3x=9 \implies x=3\).
ok, so move the -6y to the other side to get 3x+6y=9. For this specific problem, multiply the first equation by -1 to get -3x-6y=-9. Add the two equations up to get 2y=0. y=0. Substitute 0 into the second or first equation. I will do the first equation. 3x=9-6(0). 3x=9. so x=3.
so whats the answer??? im confused
\(x=3\) and \(y=0\) is your answer.
omGGGGGGGGGGGGGG THANKSSS SO FREAKING MUCH!
:))))))))))))))) delighted to help.
anwarA can you help me again?
If you give me a medal :D
i did
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-10x - 6y=0 -4x - 6y=54
Congrats some1!!
Subtract (2) from (1), you should get \(-6x=-54 \implies x=9\). Plug this in either equation, you find \(-90-6y=0 \implies y=15\).
thanks but whats x?
x=9
Wait!
ugh!! to late i already got it wrong flutterkkkk! =((((((((((
i hate negatives.
y=-15.. Just a tyop.
Sorry for that :(
but thanks any way =( will u be on this tommarrow?
I don't know!!
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