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INtegral
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\[\int\limits \sin2x\]
dx
Use substitution u=2x and see what you can get from there
I tried a different way, I did u=2x already but this time I am doing by supposing sin 2x=2sinxcosx
i got totally different answer so I am looking for help
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it is possible to have different answer, but you can see that they only differ by a constant
Using your method you get sin^2 x +C
Using substitution method we get (-1/2)cos(2x) +C
But notice that (-1/2)cos(2x) = (-1/2) ( 1 - 2sin^2 x )= -1/2 + sin^2 x
so (-1/2) cos(2x) and sin^2 x have the same derivative.
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i.e., they are both antiderivative of sin(2x)
thanks those were the answers I got
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