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Mathematics 14 Online
OpenStudy (anonymous):

INtegral

OpenStudy (anonymous):

\[\int\limits \sin2x\]

OpenStudy (anonymous):

dx

OpenStudy (watchmath):

Use substitution u=2x and see what you can get from there

OpenStudy (anonymous):

I tried a different way, I did u=2x already but this time I am doing by supposing sin 2x=2sinxcosx

OpenStudy (anonymous):

i got totally different answer so I am looking for help

OpenStudy (watchmath):

it is possible to have different answer, but you can see that they only differ by a constant

OpenStudy (watchmath):

Using your method you get sin^2 x +C

OpenStudy (watchmath):

Using substitution method we get (-1/2)cos(2x) +C

OpenStudy (watchmath):

But notice that (-1/2)cos(2x) = (-1/2) ( 1 - 2sin^2 x )= -1/2 + sin^2 x

OpenStudy (watchmath):

so (-1/2) cos(2x) and sin^2 x have the same derivative.

OpenStudy (watchmath):

i.e., they are both antiderivative of sin(2x)

OpenStudy (anonymous):

thanks those were the answers I got

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