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Mathematics 13 Online
OpenStudy (anonymous):

I'm so confused! okay! Rearrange into transformational form and state the vertex! Y=-2X^2-12x+54 -1/2 Y =X^2 +6X-27 -1/2Y +27 = X^2+12X -1/2Y+27 = X^2+12X+9-9 -1/2Y+27 = (X+3)^2 - 9 -1/2Y+36 = (X+3)^2 The vertex that I'm given for the answer is: (-3, 72) Where did I go wrong? I'm getting -3 and -36 for my vertex.

OpenStudy (cruffo):

All you need to do is finish solving for Y :)

OpenStudy (anonymous):

How would I go about that? I know 36(2) would be 72 but I'm lost as to how he got there (my teacher) Isn't transformational form supposed to be 1/A(Y-K) = (X-H)^2??

OpenStudy (cruffo):

First subtract 36 from both sides, \[-\frac{1}{2}y = (x+3)^2-36\] Then multiply both sides by -2, \[y = -2(x+3)^2 + 72\] Now, this is in the form \[y= a(x-h)^2+k\] here the vertex is (h,k) - note the sign change on h.

OpenStudy (cruffo):

To get it to look like what you posted above, you could factor out -1/2. \[-\frac{1}{2}(y-72) = (x+3)^2\]

OpenStudy (cruffo):

Sorry I didn't mention that earlier, I didn't understand what "transformational form" was.

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