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Mathematics 16 Online
OpenStudy (anonymous):

limits...wait a min for the equation

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0+}1/x -1/sinx\]

OpenStudy (anonymous):

infinity-infinity

OpenStudy (anonymous):

as x goes to 0+ infinity what happens to y on the graph that's what it's asking you

OpenStudy (anonymous):

we need to use lopetal rule

OpenStudy (anonymous):

and or 0

OpenStudy (anonymous):

L'hospitals rule

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

i am stuck while taking derivative of xsinx

OpenStudy (anonymous):

Wikipedia has everything, i'm not sure how this thing works. as well as i should. as i see it, it's what i've said above. concerning this.

OpenStudy (anonymous):

xcosx + (1)sinx

OpenStudy (anonymous):

is the derivative of xsinx

OpenStudy (anonymous):

and the derivative of the top is 1-cosx, which as x approaches 0 = 0, cuz cosx approaches 1

OpenStudy (anonymous):

what about xcoxx?

OpenStudy (anonymous):

of course, then u need to do it again lol, and xcosx derived equals -xsinx +cosx

OpenStudy (anonymous):

so the answer is 0 right?

OpenStudy (anonymous):

so the final thing will be sinx/(-xsinx +2cosx)

OpenStudy (anonymous):

and yes, the answer is 0

OpenStudy (anonymous):

thanks

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