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OpenStudy (anonymous):
x> 11/104
OpenStudy (anonymous):
312x - 11>21
adding 11 to both sides we get
312x> 33
dividing both sides by 312 we get
x>33/312
x>11/104 (cancelling out the common factor 3 from both numerator and denominator)
OpenStudy (anonymous):
x has to be less than four
OpenStudy (anonymous):
and greater than -3
OpenStudy (watchmath):
Is that absolute value?
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OpenStudy (anonymous):
\[3 I 2x-1 I >21 where as 3(2x-11)>-21 or 3(2x-11)>21\]
OpenStudy (anonymous):
\[2x-11>-7,2x>-7+11,x>2\]
OpenStudy (anonymous):
\[2x-11>7,2x>18,2x \div2>18\div2,x>9\]
OpenStudy (anonymous):
ur answers
OpenStudy (anonymous):
your using one of the absolute values but not the other it would be 11 instead it would be one
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OpenStudy (anonymous):
i mean it wouldn't be 11 instead it would be one
OpenStudy (anonymous):
okay using these steps solve those
OpenStudy (anonymous):
OHHHH!! I read it as 312x-11 !!!! My bad .....
OpenStudy (anonymous):
so the final answer would be -3<x<4
OpenStudy (anonymous):
x>4 or x<-3
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OpenStudy (anonymous):
\[3\left| 2x-1 \right|>21\]
\[ \left| 2x-1 \right|>7\]
\[2x-1>7 or -2x+1>7 \]
x>4 Or x<-3