Question

2+18i/-9i

Answer 1

Multiply top and bottom by the conjugate of -9i. Namely, 9i. The simplify.

Answer 2

I guess it is (2+18i)/-9i
multiply the numerator and the denominator by i
(2i-18)/9=2i/9 -2

Answer 3

as i^2=-1

Answer 4

ans is 0 (zero)

Answer 5

correct answer was -2+2/9i

Answer 6

Lol no? If you multiply top and bottom by the complex conjugate, you don't get a complex number back in your denominator.

Answer 7

but -2 +2 = 0

Answer 8

I.e., thats the point.

Answer 9

well the sight i use for my math class says that was the corrrect answer

Answer 10

You have:
\[2+\frac{(18i)(9i)}{(-9i)(9i)}=2+\frac{-162}{81}=2+(-2)=0\].
Alternatively:
\[\frac{(2+18i)(9i)}{(-9i)(9i)}=\frac{18i-162}{81}=\frac{2i-18}{9}\].

Answer 11

You had no ()'s so I couldn't tell.