Question

Find the area of an isosceles triangle with a base of length 12 cm and congruent of length 10 cm.

Answer 1

use Herons' Formula...

Do you know this formula??????

Answer 2

12^2+b^2=10^2

Answer 3

Why r u using Pythagoras theorem here????? it is valid only for right angled triangles...

Answer 4

according to Heron's formula

area of a triangle = sqroot[s(s-a)(s-b)(s-c)

a+b+c
where s = -------
2
and a, b and c are the lengths of the three sides of the triangle

Answer 5

From the figure u hv sent, it appears we first hv to find the height using the Pythagoras theorem

In an isosceles triangle, the perpendicular from the vertex bisects the opposite side into two equal pcs of 6 cm each

So in the Right angles triangle we have Hypotenuse = 10cm and base = 6cm

(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2
Here it becomes

10^2 = 6^2 + (P)^2
100 = 36 + (P)^2
100-36 = (P)^2
64=(P)^2
root64 = P
8 =P

So u hv height 8 cm

Area = 1/2 x base x height = 1/2 x 12 cm x 8 cm
area = 96/2 cm^2 = 48 cm^2