Question

How many digits does the number 2^1000 contain?

Answer 1

I guess 301

Answer 2

301

Answer 3

302 :D

Answer 4

well that's lame -.-

Answer 5

sorry :)

Answer 6

lol that's alright

Answer 7

do they have an explanation?

Answer 8

mostly

Answer 9

As 21000 is not a multiple of 10, it follows that,
10m 21000 10m + 1, where 10m contains m + 1 digits.
Solving 21000 = 10k, where m k m + 1
k = log 21000 = 1000 log 2 301.02999... , so m = [1000 log 2] = 301.
Hence 21000 contains 302 digits.
What

Answer 10

some things did not copy paste nicely :)

Answer 11

http://mathschallenge.net/problems/pdfs/mathschallenge_4_star.pdf

Answer 12

alright I'm done for today, thanks for the problems :)

Answer 13

It was enough for me too