what is an equation of the circle whose diameter ab has endpoints a (-4,2) and b(4,4)

Question

amistre64 · Answer

stack your points subtract them and you get your distances on x and y for the pythag

amistre64 · Answer

-4,2
-(4,4)
------
-8, -2;   x = 8 and y = 2  distance = sqrt(x^2 +y^2)

amistre64 · Answer

sqrt(64 +4) = sqrt(68)

anonymous · Answer

or find the midpoint.  midpoint is 
$$(\frac{-4+4}{2},\frac{2+4}{2})$$ i.e. (0,3)

amistre64 · Answer

pull the 4 out and get 2sqrt(17)  divide in half to get radius

amistre64 · Answer

rad = sqrt(17)

amistre64 · Answer

middies good for center point of equation yes ;)

amistre64 · Answer

(x-Cx)^2 +(y-Cy)^2 = 17  then

anonymous · Answer

now find the distance from the midpoint to one endpoint.  forget about taking the square root because you formula will have a square in it.  
$$(4-0)^2+(4-3)^2=16+1=17$$

anonymous · Answer

so your equation is 
$$(x-0)^2+(y-3)^2=17$$ better known as 
$$x^2+(y-3)^2=17$$

anonymous · Answer

hello amistre.  been here for a while?

anonymous · Answer

THANXZ

amistre64 · Answer

i been here since about  well..... lost track

anonymous · Answer

-4,2
-(4,4)
------
-8, -2;   x = 8 and y = 2  distance = sqrt(x^2 +y^2)