Question

solve for x
2(x-4)+(x+2)=(x+2)(x-4)

Answer 1

\[2x-8+x+2=x^2-2x-8\]
\[3x+6=x^2-2x-8\]
\[x^2-5x-14=0\]
\[(x-7)(x+2)=0\]
\[x-7=0\]
\[x=7\]
\[x+2=0\]
\[x=-2\]

Answer 2

that is not correct?

Answer 3

ok let me try it again. maybe an algebra mistake

Answer 4

tsk tsk tsk.....

Answer 5

sorry master...

Answer 6

oh damn it was -6 not 6!

Answer 7

2(x-4)+(x+2)=(x+2)(x-4)

2x-8 +x+2 = x^2 -2x -8

3x -6 = x^2 .......

Answer 8

how many times I gotta clean up your messes lol

Answer 9

\[3x-6=x^2-2x-8\]
\[x^2-5x-14=0\]

Answer 10

another mistake!

Answer 11

\[x^2-5x-2=0\] whew

Answer 12

the cape and cowl are going back to the store ......

Answer 13

answer is
\[x=\frac{5\pm\sqrt{33}}{2}\]

Answer 14

damned algebra kills me every time. where did i get a +6 from??

Answer 15

now pt jessica it is right.

Answer 16

trying to type, latex, and math at the same time; you lack discipline my child...

Answer 17

trust me or the master puts me back in the dungeon

Answer 18

i am going to get you to use latex eventually...

Answer 19

as long as my extra finger aint doin nuthin it might as well take up the latex lol

Answer 20

so, what is the answer again?

Answer 21

\[2(x - 4) + (x+2) = (x+2)(x-4)\]
\[2x-8 + x + 2 = x ^{2} - 4x + 2x - 8\]
\[x ^{2} - 5x -2 = 0\]
\[\Delta=25-4*1*(-2) = 25 + 8 = 33\]
\[x=-(-5) + \sqrt{33}/2
or
x=-(-5)-\sqrt{33}q2\]

Answer 22

\[solution 1, x=(\sqrt{33}+5)/2 solution 2, x=(5-\sqrt{33})/2\]