Mathematics
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OpenStudy (anonymous):
i am wondering is this correct? (x^3+2x^2-3x^2+2)div(x+1) = x^2-2x+2?
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OpenStudy (anonymous):
Yes it is.
OpenStudy (anonymous):
means
\[-3x\] not
\[-3x^2\] yes?
OpenStudy (anonymous):
is the question correct???????????/
OpenStudy (anonymous):
because i think either way it is wrong
OpenStudy (anonymous):
wrong?
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OpenStudy (anonymous):
its correct. all abouve me can flutter off.
OpenStudy (anonymous):
lol @mariaisme
OpenStudy (anonymous):
It's correct!
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
No, it's not correct :(
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OpenStudy (anonymous):
\[(x^3+2x^2-3x^2+2)\div(x+1)\] this is how u supposed to write it
OpenStudy (anonymous):
Damn it!! What's wrong with me?! Final answer: CORRECT :D
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
The best way to do it is to use long division!
OpenStudy (anonymous):
correct !
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OpenStudy (anonymous):
correct !
OpenStudy (anonymous):
ok by why not subtract first?
OpenStudy (anonymous):
The numerator is\(x^3-x^2+2=(x+1)(x^2-2x+2)\). The (x+1) part will get cancelled with denominator and you'll be left with \(x^2-2x+2\).
OpenStudy (anonymous):
\[x^3+2x^2-3x^2+2=x^2-x^2+2\] yes?
OpenStudy (anonymous):
that is why i thought it was messed up. but it is right!
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OpenStudy (anonymous):
thank you guys it been helpful