the equation of the tangent line to the graph of f(x) at (5, 52) is y=mx+b for

m=25 and b=?

f(x) = 3x^2-5x+2

Question

the equation of the tangent line to the graph of f(x) at (5, 52) is y=mx+b for

m=25 and b=?

f(x) = 3x^2-5x+2

amistre64 · Answer

m = f'(x) sooo

y = (6(5) -5)(x-5)+52

anonymous · Answer

thanks, how did you get that?

amistre64 · Answer

well, they already gave the slope so the derivative was just a throw in

amistre64 · Answer

but given a point P(x,y) and a slope of m; the equation can be determined by:

y = m(x-Px)+Py

anonymous · Answer

ahh, I see what I was doing wrong.

amistre64 · Answer

where Py = the b part...

amistre64 · Answer

you can get there quicker by:

y = mx -mPx + Py maybe :)

anonymous · Answer

yeah, that worked. thanks again

amistre64 · Answer

youre welcome :)

anonymous · Answer

how would you get the intercept for this one then?
f(x)=$$\sqrt{6-x}$$
m=-.25

anonymous · Answer

the slope is given by the derivative at x=2

anonymous · Answer

crap, not slope. I meant intercept.

amistre64 · Answer

the intercept is rather vague; do you mean the x intercept of the tangent line to the curve at x=2?