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Mathematics 18 Online
OpenStudy (anonymous):

PLEASE can some one attempt this: Given: as x goes to c for all functions[ f(x)=2; g(x)=0, h(x)=3] evaluate the limit as x goes to c for: h(x)/(x-c)

OpenStudy (anonymous):

Hey Sat: I cannot figure out what c is:

OpenStudy (anonymous):

I assume you have to use rules

OpenStudy (anonymous):

well first of all we know that h(x) = 3 yes?

OpenStudy (anonymous):

a) 3 b) - 2⁄3 c) 3⁄2 d) 0 e) does not exist

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

3/(x-c)

OpenStudy (anonymous):

i mean that is given

OpenStudy (anonymous):

yes given

OpenStudy (anonymous):

ok and we want the limit as x -> c yes?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

now the denominator obviously goes to 0

OpenStudy (anonymous):

and we know for f(x) it is 2 and for g(x) it is 0

OpenStudy (anonymous):

i don't care what c is, it doesn't matter. the limit as x -> c of x - c = 0 for sure

OpenStudy (anonymous):

please explain why?

OpenStudy (anonymous):

oh because as x goes to c, well... x goes to c. therefore x - c (the difference) goes to zero. it is just that

OpenStudy (anonymous):

ok, got you!

OpenStudy (anonymous):

lets imagine c was 5 and i asked you to compute the limit as x -> 5 of x - 5. you would say it is zero. at least i hope you would

OpenStudy (anonymous):

that makes sense, intuitive actually

OpenStudy (anonymous):

good

OpenStudy (anonymous):

haha! I would!

OpenStudy (anonymous):

therefore the limit does not exist as the denom is 0

OpenStudy (anonymous):

so the limit is the denominator is 0 we have established that fact

OpenStudy (anonymous):

in order for the limit of the whole fraction to exist, that means the limit in the numerator must also be zero. if it is not, there is no limit

OpenStudy (anonymous):

i can go further if i substitute and get 0/0

OpenStudy (anonymous):

maybe factor and cancel, or something more fancy

OpenStudy (anonymous):

but if the limit in the numerator is a non - zero number, then i have no hope

OpenStudy (anonymous):

i cannot go further if i see 2/0 for example. no limit

OpenStudy (anonymous):

it was understanding that x goes to c, would also mean that x-c has to be zero - that is what stumped me

OpenStudy (anonymous):

and since we know the numerator is identically 3, you are trying to compute the limit as x -> c of 3/(x-c) which does not exist

OpenStudy (anonymous):

great explanation! should get bonus medal

OpenStudy (anonymous):

well now you are not stumped i hope

OpenStudy (anonymous):

def not, you are absolutely awesome!

OpenStudy (anonymous):

i am stumped as to why this question included an f and a g. are there other parts maybe?

OpenStudy (anonymous):

no other parts, think just to confuse

OpenStudy (anonymous):

yeah i see that. ok good luck, think you are doing fine

OpenStudy (anonymous):

thank you, been a long time since I did calc;

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