Question

Please solve x2-x-30/x-5=11 and please show work.

Answer 1

answer is
\[6\pm\sqrt{11}\]

Answer 2

here is the work

Answer 3

\[\frac{x^2-x-30}{x-5}=11\]
\[x^2-x-30=11(x-5)\]
\[x^2-x-30=11x-11\]
\[x^2-12x-19=0\]

Answer 4

now you have a choice, quadratic formula or completing the square. will give the same answer but since 12 is even i choose to complete the square

Answer 5

typo
\[x^2-x-30=11x-55\]
\[x^2-12x+15=0\]

Answer 6

still i complete the square
[x^2-12x=-15\]
\[(x-6)^2=-15+6^2\]
\[(x-6)^2=11\]
\[x-6=\pm\sqrt{11}\]
\[x=6\pm\sqrt{11}\]

Answer 7

for 11(x-5 ) how did you get 11x-11 if 11x5 is 55 ?

Answer 8

that was a mistake that i corrected further down. sorry. where i wrote "typo" i corrected that mistake

Answer 9

oh i see it. thanks alot :)

Answer 10

yw

Answer 11

x2-x-30/x-5=11
x2-x-30 = 11(-x+5)
x2-x-30 = -11x+ 55
x2+10x=55+30
x2+10x=85
x2+10x-85=0
\[\Delta = B ^{2}-4ac\]
100x-4(1*85)
100x-340
x= -340/100
x= -3,4

Answer 12

fraid that is not right

Answer 13

how did you get 85?

Answer 14

Im suppose to get one answer. how do i know which either one is right?