Mathematics
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OpenStudy (anonymous):
Is it possible to have a function f defined on [ 4 , 6 ] and meets the given conditions?
f is continuous on [ 4 , 6 ], takes on no rational vales.
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OpenStudy (anonymous):
answer is no _ i think
OpenStudy (anonymous):
no
OpenStudy (anonymous):
not if you believe there are irrational numbers between 4 and 6 !
OpenStudy (anonymous):
lol!
OpenStudy (anonymous):
oops
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OpenStudy (anonymous):
it is wrong
OpenStudy (anonymous):
what about this nice continuous function
\[f(x)=\pi+1\]
OpenStudy (anonymous):
it is continuous everywhere, and takes on no rational values
OpenStudy (anonymous):
guess i should read carefully before i answer
OpenStudy (anonymous):
no.......
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OpenStudy (anonymous):
satellite always gets the better of me
OpenStudy (anonymous):
any constant function will do.
\[f(x)=\sqrt{2}\] etc
OpenStudy (anonymous):
sheer luck
OpenStudy (anonymous):
when did trained dogs start courting lady luck :P
OpenStudy (anonymous):
one day i will be a master, then a guru...
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OpenStudy (anonymous):
so then the answer is no?
OpenStudy (anonymous):
the answer is
"yes it is possible"
OpenStudy (anonymous):
i see
OpenStudy (anonymous):
do you understand why? a constant function is continuous.
OpenStudy (anonymous):
yes, there is no discontinuity
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OpenStudy (anonymous):
what I am trying to see is how it can take no rational value between [4,6]