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Mathematics 16 Online
OpenStudy (anonymous):

Is it possible to have a function f defined on [ 4 , 6 ] and meets the given conditions? f is continuous on [ 4 , 6 ], takes on no rational vales.

OpenStudy (anonymous):

answer is no _ i think

OpenStudy (anonymous):

no

OpenStudy (anonymous):

not if you believe there are irrational numbers between 4 and 6 !

OpenStudy (anonymous):

lol!

OpenStudy (anonymous):

oops

OpenStudy (anonymous):

it is wrong

OpenStudy (anonymous):

what about this nice continuous function \[f(x)=\pi+1\]

OpenStudy (anonymous):

it is continuous everywhere, and takes on no rational values

OpenStudy (anonymous):

guess i should read carefully before i answer

OpenStudy (anonymous):

no.......

OpenStudy (anonymous):

satellite always gets the better of me

OpenStudy (anonymous):

any constant function will do. \[f(x)=\sqrt{2}\] etc

OpenStudy (anonymous):

sheer luck

OpenStudy (anonymous):

when did trained dogs start courting lady luck :P

OpenStudy (anonymous):

one day i will be a master, then a guru...

OpenStudy (anonymous):

so then the answer is no?

OpenStudy (anonymous):

the answer is "yes it is possible"

OpenStudy (anonymous):

i see

OpenStudy (anonymous):

do you understand why? a constant function is continuous.

OpenStudy (anonymous):

yes, there is no discontinuity

OpenStudy (anonymous):

what I am trying to see is how it can take no rational value between [4,6]

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