find the parametric for the line with the following properties. the line passes through the origin, it is contained in a plane 2x + 3y - z = 0, and is orthogonal to the vector v = <4,1,2>.
please show some work
wel the normal vector to the plane is <2,3,-1> now the line is perpendicular to it as it lies in the plane it is also perp to <4,1,2> so it is parallel to the vector product of these 2
which is <7, -8, -10>
So cross <2,3,-1> and <4,1,2> Then you have a vector parallel to the line and a point that the line goes through (namely, the origin). So the line should be x=7t y=-8t z=-10t Right him?
since it passes through the origin, the line is r = tb the rest malevolence has done
:D
thanks
thank you guys, ur awesome :P
dont mention it..were only droplets in the river of god
oh, I thought we were only droplets in the river of rama.
god is god..no matter what u call god
Bhuda bless.
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