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Mathematics 26 Online
OpenStudy (annon):

find the parametric for the line with the following properties. the line passes through the origin, it is contained in a plane 2x + 3y - z = 0, and is orthogonal to the vector v = <4,1,2>.

OpenStudy (annon):

please show some work

OpenStudy (anonymous):

wel the normal vector to the plane is <2,3,-1> now the line is perpendicular to it as it lies in the plane it is also perp to <4,1,2> so it is parallel to the vector product of these 2

OpenStudy (anonymous):

which is <7, -8, -10>

OpenStudy (anonymous):

So cross <2,3,-1> and <4,1,2> Then you have a vector parallel to the line and a point that the line goes through (namely, the origin). So the line should be x=7t y=-8t z=-10t Right him?

OpenStudy (anonymous):

since it passes through the origin, the line is r = tb the rest malevolence has done

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

thanks

OpenStudy (annon):

thank you guys, ur awesome :P

OpenStudy (anonymous):

dont mention it..were only droplets in the river of god

OpenStudy (anonymous):

oh, I thought we were only droplets in the river of rama.

OpenStudy (anonymous):

god is god..no matter what u call god

OpenStudy (anonymous):

Bhuda bless.

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