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Apply the chain rule, in Leibniz notation, to determine dy/dx at the indicated value of x. a) y=u^2 +3u, u=Square root of x-1, x=5.
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you can determine dy/du ; and du/dx so multiply them together to get dy/dx
dy/dx = dy/du * du/dx = 2u+3 * 1/2(1/sqrt(x-1)) = 71/4 or -1/4
Dhatraditya when you do that, you get 7 as your answer...
you should get 7/4 or 1/4 as the answer
you would get this \[(2(\sqrt{5-1)}+3(1/2(5-1)^{1/2}\]
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sorry it is \[\frac{2\sqrt{x-1}+3}{2\sqrt{x-1}}\]
sqrt 4 gives two values, +2 and -2 with +2 you get 7/4 with -2 you get -1/-4 = 1/4
Ahhh... okay, Thanks. such a fail on my part :P
you are welcome
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