f(x)= sqrt (x+2) g(x)= sqrt (x-1) find (f*g)(x) (f/g)(x) also find the domain of each
does the asterisk mean compostion?
like the first part is f(g)
you want \[f\circ g(x)\]?
yes
not sure how you did the little circle
ok so it is \[f \circ g(x) = f(g(x))=f(\sqrt{x-1})\]
=\[\sqrt{\sqrt{x-1}+2}\]
yes then you have to substitute f(x) in for the x
no you put g(x) where you see x in f(x)
do it step by step as i did and you will not mess this up
k i get the first part now :)
what about f/g
now you need domain yes?
\[\frac{f}{g}\] is trivial, just put f on top of g
k
hey satellite, can u come to chat if u don't mind
\[\frac{f}{g}(x)=\frac{f(x)}{g(x)}=\frac{\sqrt{x+2}}{\sqrt{x-1}}\]
now we do the domain. domain of f/g is x > 1 since the thing under the radical must be non - negative,and since it is in the denominator it cannot be 0 either. that is why you need the strict inequality.
harder is first one
@krish now that you mention it i do not see chat!
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