Find dy/dx by implicit differentiation.
x^5+y^3=4....i got (-5x^4)/(y^2)....

Question

amistre64 · Answer

implicit is just the same as explicit; just a new name thats all

anonymous · Answer

im just learning the chapter now...

amistre64 · Answer

x^5 + y^3 = 4

Dx(x^5) +Dx(y^3) = Dx(4)

x' 5x^4 + y' 3x^2 = 0  ; x'=1; solve for y'

amistre64 · Answer

i typoed it;  thats spose to be y' 3y^2 :)

anonymous · Answer

yes..but wouldnt you have to solve it..to be come..$$3y^2y^'=-5x^4....$$

anonymous · Answer

and divide it by $$3y^2?$$

amistre64 · Answer

differentiating is the same regardless of what you call it; explicit, implicit or other....

yes, that is correct; the only thing you left out in your post was the '3'

anonymous · Answer

to get $$-5x^4/3y^2$$

amistre64 · Answer

yep

anonymous · Answer

ooohh haha silly me

amistre64 · Answer

yeah :)

I took a test the other day and derived fine; but I misplaced a sign.. grrr

anonymous · Answer

i know i hate it when that happens