I am solving a quadratic equation and I and my a term is 22r^2, b term is 19r and c is 4. How would I factor this?

Question

anonymous · Answer

is the equation$$22r ^{2} + 19r + 4 = 0  ???$$

anonymous · Answer

Yes, but it doesn't say what it equals.

anonymous · Answer

ok so u want to factorise it..
proceed as follows
here a = 22 and c=4       so ac = 88
we have to split 88 into two factors A and B so tha AB = 88 and A+B = 19
88 = 2x44 , 4x22, 8x11
out of these combinations,  8x11 fulfills our requirement
8x11 = 88 and 8+11 = 19

so 22r^2 + 19r + 4 = 22r^2 + 8r + 11r + 4
                                  = 2r(11r +4) +1(11r +4)
                                  = (2r+1)(11r+4)

this way you get two factors of the give quadratic equation

anonymous · Answer

If answer is clear, pls click GOOD ANSWER button for me....  :))

anonymous · Answer

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