Find an equation of the tangent line to the curve at the point (7, 2).

http://www.webassign.net/cgi-bin/symimage.cgi?expr=y%20%3D%20%28x%20-%205%29%2F%28x%20-%206%29

Question

Find an equation of the tangent line to the curve at the point (7, 2).

http://www.webassign.net/cgi-bin/symimage.cgi?expr=y%20%3D%20%28x%20-%205%29%2F%28x%20-%206%29

anonymous · Answer

take the derivative using the quotient rule, plug in 7 to get the slope.

anonymous · Answer

Differentiate it:
Quotient rule gives:
(x-6)-(x-5)
---------
(x-6)^2
Plugging in 7 you get:
-1?
So then you have point slope form:
y-y_0=m(x-x_0)
y-2=-(x-7)
y=-x+9

anonymous · Answer

i get 
$$y'-\frac{-1}{(x-6)^2}$$

anonymous · Answer

malevolence has it, but i would have simplified the numerator first

anonymous · Answer

:P I thought about it but I'm lazy xP

anonymous · Answer

Thank you guys!

anonymous · Answer

No problem :P