Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

how do you find the values of x for which the series (x+1)^n from n=1 to infinity converges?

OpenStudy (anonymous):

from -2 to 0 yes

OpenStudy (amistre64):

they gotta make it a fraction in there

OpenStudy (anonymous):

guru don't you even sleep?

OpenStudy (anonymous):

nvm, its ratio test right?

OpenStudy (amistre64):

i thought i was asleep lol been doing algebra all day and its soooo boring

OpenStudy (anonymous):

\[\sum x^n\] converges for (-1,1) so \[\sum(x+1)^n \] just move over one. i think it is that simple

OpenStudy (anonymous):

yeah I had found it, thanks for the help though guys

OpenStudy (anonymous):

i am sure you can use a test if you like but there is no difference between x and x +1. if the first converges on (-1,1) the second does on (-2,0)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!