Question

how do u find the maximum for r=4sin2(theta)? is sq2/2 wrong?

Answer 1

r=4 is the max..

Answer 2

does the 2 in front of the theta not affect the maximum in any way?

Answer 3

any sinusoidal function has max of 1 so r max=4*1=4

Answer 4

the two will not affect in the max. value of r but it will affect the value for which the max. occurs..
if it is 4sin (theta) then theta=pi/2 for maxima..but if it is

r=4sin (a theta) then theta= pi/(2a)

Answer 5

thanks! what if there's a number in front of the sin theta like in r=3-5sin2theta? how would that change the maximum?

Answer 6

r will be maximum when 5 sin 2theta is minimum...because it is subtracted from 3...
so minimum of sin x is -1
so rmax=3-5*(-1)=3+5=8
sin 2theta=-1
theta=-pi/4

Answer 7

sorry i meant r=3-5cos2theta but the minimum of cosx is also -1 so the final answer would still be the same right?