Question

Pls integrate following
Integration sign x/x^2 +1 dx

Answer 1

\[\int\limits\frac x{x^2+1}dx\]let x^2+1=y
2xdx=dy
xdx=dy/2
\[\frac12\int\limits\frac {dy}y=\frac12 \ln(y) +c\]\[\frac12 \ln(x^2+1)+c=\ln \sqrt{x^2+1}+c\]

Answer 2

got it??

Answer 3

Nopes hehehe but what if we take x common in x^2+1

Answer 4

do it..then i'll understand what u want to know exactly??

Answer 5

Like x(x+1/x)

Answer 6

yes..thats possible

Answer 7

\[\ln \sqrt{x(x+\frac1x)}+c\]